What is the integral from-1 to 1 of sin(t) ?

The integral from-1 to 1 of sin(t) is 0

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integral from-1 to 1 of sin(t)

\int_{- 1}^{1} sin (t) d t

0

Solution steps

\int_{- 1}^{1} sin (t) d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (t) :

Odd

= 0

\int_{- 7}^{- 2} 2 - x d x

\int_{0}^{1} 4 x e^{5 x} d x

\int_{0}^{1} \frac{1}{( 1 + 2 y ) ^{3}} d y

\int_{0}^{0.8} \frac{1}{1 - x} d x

\int_{0}^{1} 1 \cdot x d x

What is the integral from-1 to 1 of sin(t) ?
The integral from-1 to 1 of sin(t) is 0