What is the integral from 0 to 1 of (10x) ?

The integral from 0 to 1 of (10x) is 5

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integral from 0 to 1 of (10x)

\int_{0}^{1} (10 x) d x

5

Solution steps

\int_{0}^{1} 10 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= 10 [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 10 \cdot \frac{1}{2}

Simplify

= 5

\int_{- 1}^{1} \frac{6 x}{( x + 6 ) ^{2}} d x

\int_{3}^{9} 1 + x^{3} d x

\int_{- 2}^{+ 2} \frac{1}{x ^{3}} d x

\int_{0}^{1} x (1 - x) d x

What is the integral from 0 to 1 of (10x) ?
The integral from 0 to 1 of (10x) is 5