What is the integral from 4 to sqrt(25-x^2-y^2 of)1 ?

The integral from 4 to sqrt(25-x^2-y^2 of)1 is sqrt(25-x^2-y^2)-4

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integral from 4 to sqrt(25-x^2-y^2 of)1

\int_{4}^{25 - x^{2} - y^{2}} 1 d z

25 - x^{2} - y^{2} - 4

Solution steps

\int_{4}^{25 - x^{2} - y^{2}} 1 d z

Integral of a constant:

\int a d x = a x

= [1 \cdot z]_{4}^{25 - x^{2} - y^{2}}

Simplify

= [z]_{4}^{25 - x^{2} - y^{2}}

Compute the boundaries:

25 - x^{2} - y^{2} - 4

= 25 - x^{2} - y^{2} - 4

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What is the integral from 4 to sqrt(25-x^2-y^2 of)1 ?
The integral from 4 to sqrt(25-x^2-y^2 of)1 is sqrt(25-x^2-y^2)-4