What is the integral from 0 to cos(y) of sin(y) ?

The integral from 0 to cos(y) of sin(y) is -cos(cos(y))+1

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integral from 0 to cos(y) of sin(y)

\int_{0}^{c o s (y)} sin (y) d y

- cos (cos (y)) + 1

Solution steps

\int_{0}^{c o s (y)} sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= [- cos (y)]_{0}^{c o s (y)}

Compute the boundaries:

- cos (cos (y)) + 1

= - cos (cos (y)) + 1

\int_{0}^{x^{2}} x^{2} (1 + x) d x

\int_{- 2}^{1} 5 - x^{2} d x

\int_{- 1}^{1} - t \cdot e^{- i wt} d t

\int_{\frac{π}{4}}^{\frac{π}{2}} ln (sin (x)) d x

\int_{0}^{x} \frac{1}{1 + x} d x

What is the integral from 0 to cos(y) of sin(y) ?
The integral from 0 to cos(y) of sin(y) is -cos(cos(y))+1