What is the integral from 0 to pi/2 of sec(x)-tan(x) ?

The integral from 0 to pi/2 of sec(x)-tan(x) is diverges

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integral from 0 to pi/2 of sec(x)-tan(x)

\int_{0}^{\frac{π}{2}} sec (x) - tan (x) d x

diverges

Solution steps

\int_{0}^{\frac{π}{2}} sec (x) - tan (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{2}} sec (x) d x - \int_{0}^{\frac{π}{2}} tan (x) d x

\int_{0}^{\frac{π}{2}} sec (x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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\int_{2}^{3} - x^{2} d x

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What is the integral from 0 to pi/2 of sec(x)-tan(x) ?
The integral from 0 to pi/2 of sec(x)-tan(x) is diverges