What is the integral from 0 to 1 of \sqrt[3]{t} ?

The integral from 0 to 1 of \sqrt[3]{t} is 3/4

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integral from 0 to 1 of \sqrt[3]{t}

\frac{3}{4}

Decimal Notation

0.75

Solution steps

Apply the Power Rule

: [\frac{3}{4} t^{\frac{4}{3}}]_{0}^{1}

= [\frac{3}{4} t^{\frac{4}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

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What is the integral from 0 to 1 of \sqrt[3]{t} ?
The integral from 0 to 1 of \sqrt[3]{t} is 3/4