What is the integral from 500 to 10x+500 of 1/75000 ?

The integral from 500 to 10x+500 of 1/75000 is (x+50)/(7500)-1/150

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integral from 500 to 10x+500 of 1/75000

\int_{500}^{10 x + 500} \frac{1}{75000} d y

\frac{x + 50}{7500} - \frac{1}{150}

Solution steps

\int_{500}^{10 x + 500} \frac{1}{75000} d y

Integral of a constant:

\int a d x = a x

= [\frac{1}{75000} y]_{500}^{10 x + 500}

Compute the boundaries:

\frac{x + 50}{7500} - \frac{1}{150}

= \frac{x + 50}{7500} - \frac{1}{150}

\int_{0}^{1} \frac{x ^{3}}{3 x ^{4} + 1} d x

\int_{1}^{2} (x + x)^{2} d x

\int_{0}^{1} 2 x e^{3 x} d x

\int_{- 2}^{1} x^{2} - x + 2 d x

\int_{0}^{2} x^{2} - 5 d x

What is the integral from 500 to 10x+500 of 1/75000 ?
The integral from 500 to 10x+500 of 1/75000 is (x+50)/(7500)-1/150