What is the integral from z to y of 1/x ?

The integral from z to y of 1/x is ln|y|-ln|z|

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integral from z to y of 1/x

\int_{z}^{y} \frac{1}{x} d x

ln ∣ y ∣ - ln ∣ z ∣

Solution steps

\int_{z}^{y} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{z}^{y}

Compute the boundaries:

ln ∣ y ∣ - ln ∣ z ∣

= ln ∣ y ∣ - ln ∣ z ∣

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What is the integral from z to y of 1/x ?
The integral from z to y of 1/x is ln|y|-ln|z|