What is the integral from-2 to 2 of sqrt(1-x^2) ?

The integral from-2 to 2 of sqrt(1-x^2) is 4sqrt(1-x^2)

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integral from-2 to 2 of sqrt(1-x^2)

\int_{- 2}^{2} 1 - x^{2} d y

4 1 - x^{2}

Solution steps

\int_{- 2}^{2} 1 - x^{2} d y

Integral of a constant:

\int a d x = a x

= [1 - x^{2} y]_{- 2}^{2}

Compute the boundaries:

4 1 - x^{2}

= 4 1 - x^{2}

\int_{0}^{1} \frac{1}{2} x^{3} + 2 d x

\int_{2}^{4} e^{2 x} d x

\int_{\frac{1}{2}}^{1} x (e - e^{x}) d x

\int_{- 1}^{1} (x^{3} - \frac{3 x}{5})^{2} d x

\int_{0}^{1} 8 x^{2} + 1 d x

What is the integral from-2 to 2 of sqrt(1-x^2) ?
The integral from-2 to 2 of sqrt(1-x^2) is 4sqrt(1-x^2)