What is (\partial)/(\partial x)(9x^2+25y^2-225) ?

The answer to (\partial)/(\partial x)(9x^2+25y^2-225) is 18x

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(\partial)/(\partial x)(9x^2+25y^2-225)

\frac{\partial}{\partial x} (9 x^{2} + 25 y^{2} - 225)

18 x

Solution steps

\frac{\partial}{\partial x} (9 x^{2} + 25 y^{2} - 225)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x^{2}) + \frac{\partial}{\partial x} (25 y^{2}) - \frac{\partial}{\partial x} (225)

\frac{\partial}{\partial x} (9 x^{2}) = 18 x

\frac{\partial}{\partial x} (25 y^{2}) = 0

\frac{\partial}{\partial x} (225) = 0

= 18 x + 0 - 0

Simplify

= 18 x

\frac{d y}{d x}, 6 x^{3} + 7 y^{3} = 13 x y

(- 1.4) (1.4)

2 arctan (x) - x

\int sin (x) d x

f (x) = x^{4} e^{x}

What is (\partial)/(\partial x)(9x^2+25y^2-225) ?
The answer to (\partial)/(\partial x)(9x^2+25y^2-225) is 18x