What is the integral from-1.5 to 1.5 of x(1.33x^2-3) ?

The integral from-1.5 to 1.5 of x(1.33x^2-3) is 0

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integral from-1.5 to 1.5 of x(1.33x^2-3)

\int_{- 1.5}^{1.5} x (1.33 x^{2} - 3) d x

0

Solution steps

\int_{- 1.5}^{1.5} x (1.33 x^{2} - 3) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x (1.33 x^{2} - 3) :

Odd

= 0

\int_{0}^{3} (x^{2} + 2 x + 3) d x

\int_{0}^{12} \frac{1}{x + 12} d x

\int_{- 2}^{1} π (x^{2} + x - 2)^{2} d x

\int_{0}^{5} 2 t d t

\int_{- 1}^{1} x^{2} + 2 x d x

What is the integral from-1.5 to 1.5 of x(1.33x^2-3) ?
The integral from-1.5 to 1.5 of x(1.33x^2-3) is 0