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Popular >

integral from 0 to 4 of (1+x/2)

Solution

\int_{0}^{4} (1 + \frac{x}{2}) d x

Solution

8

Solution steps

\int_{0}^{4} 1 + \frac{x}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 1 d x + \int_{0}^{4} \frac{x}{2} d x

\int_{0}^{4} 1 d x = 4

\int_{0}^{4} \frac{x}{2} d x = 4

= 4 + 4

Simplify

= 8

Popular Examples

integral from 1 to 4 of (u-5)/(sqrt(u))

\int_{1}^{4} \frac{u - 5}{u} d u

integral from-1 to 3 of (x^3-1)/(x^3+x)

\int_{- 1}^{3} \frac{x ^{3} - 1}{x ^{3} + x} d x

integral from 0 to 2 of 6x^5e^{x^3y}

\int_{0}^{2} 6 x^{5} e^{x^{3} y} d y

integral from 4 to 8 of 1/(x-3)

\int_{4}^{8} \frac{1}{x - 3} d x

integral from-1 to 3 of 5xsqrt(x+1)

\int_{- 1}^{3} 5 x x + 1 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (1+x/2) ?
The integral from 0 to 4 of (1+x/2) is 8