What is the integral from 0 to 1 of (14ln(x)) ?

The integral from 0 to 1 of (14ln(x)) is -14

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integral from 0 to 1 of (14ln(x))

\int_{0}^{1} (14 ln (x)) d x

- 14

Solution steps

\int_{0}^{1} 14 ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 14 \cdot \int_{0}^{1} ln (x) d x

Apply Integration By Parts

: [x ln (x) - \int 1 d x]_{0}^{1}

= 14 [x ln (x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= 14 [x ln (x) - x]_{0}^{1}

Compute the boundaries:

- 1

= 14 (- 1)

Simplify

= - 14

\int_{- 1}^{2} x^{2} - 4 d x

\int_{- 1}^{1} - z^{2} + 1 d z

\int_{- π}^{π} sin (θ) d θ

\int_{- π}^{π} π d x

\int_{- 1}^{1} x \frac{1}{2} d x

What is the integral from 0 to 1 of (14ln(x)) ?
The integral from 0 to 1 of (14ln(x)) is -14