What is the integral from 3 to 4 of 4+(24)/(x^2) ?

The integral from 3 to 4 of 4+(24)/(x^2) is 6

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integral from 3 to 4 of 4+(24)/(x^2)

\int_{3}^{4} 4 + \frac{24}{x ^{2}} d x

6

Solution steps

\int_{3}^{4} 4 + \frac{24}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{4} 4 d x + \int_{3}^{4} \frac{24}{x ^{2}} d x

\int_{3}^{4} 4 d x = 4

\int_{3}^{4} \frac{24}{x ^{2}} d x = 2

= 4 + 2

Simplify

= 6

\int_{2}^{3} \frac{4}{1 + x ^{2}} d x

\int_{- 1}^{1} x x^{2} + 3 d x

\int_{- 1}^{1} 3 x^{2} + 4 d x

\int_{0}^{2} x - 3 y^{2} d x

\int_{- 6}^{- 3} (x - \frac{3}{x ^{2}}) d x

What is the integral from 3 to 4 of 4+(24)/(x^2) ?
The integral from 3 to 4 of 4+(24)/(x^2) is 6