What is the derivative of (4+2x^2^7) ?

The derivative of (4+2x^2^7) is 28x(4+2x^2)^6

What is the first derivative of (4+2x^2^7) ?

The first derivative of (4+2x^2^7) is 28x(4+2x^2)^6

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\frac{d}{d x} ((4 + 2 x^{2})^{7})

28 x (4 + 2 x^{2})^{6}

Solution steps

\frac{d}{d x} ((4 + 2 x^{2})^{7})

Apply the chain rule:

7 (4 + 2 x^{2})^{6} \frac{d}{d x} (4 + 2 x^{2})

= 7 (4 + 2 x^{2})^{6} \frac{d}{d x} (4 + 2 x^{2})

\frac{d}{d x} (4 + 2 x^{2}) = 4 x

= 7 (4 + 2 x^{2})^{6} \cdot 4 x

Simplify

= 28 x (4 + 2 x^{2})^{6}

\int (4 sin (2 x) - 3 cos (3 x)) d x

(2 + x)^{- 2}

x \to \infty lim (\frac{2 ( x - 8 ) ^{35}}{( x - 1 ) ^{35}})

f (x) = \frac{x + 1}{x ^{2} + 1}

\frac{d y}{d t} = y^{3}, y (0) = 1

What is the derivative of (4+2x^2^7) ?
The derivative of (4+2x^2^7) is 28x(4+2x^2)^6
What is the first derivative of (4+2x^2^7) ?
The first derivative of (4+2x^2^7) is 28x(4+2x^2)^6