What is the integral from 1 to 4 of (1+t)/(sqrt(t)) ?

The integral from 1 to 4 of (1+t)/(sqrt(t)) is 20/3

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integral from 1 to 4 of (1+t)/(sqrt(t))

\int_{1}^{4} \frac{1 + t}{t} d t

\frac{20}{3}

Solution steps

\int_{1}^{4} \frac{1 + t}{t} d t

Expand

\frac{1 + t}{t} : \frac{1}{t} + t

= \int_{1}^{4} \frac{1}{t} + t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} \frac{1}{t} d t + \int_{1}^{4} t d t

\int_{1}^{4} \frac{1}{t} d t = 2

\int_{1}^{4} t d t = \frac{14}{3}

= 2 + \frac{14}{3}

Simplify

2 + \frac{14}{3} : \frac{20}{3}

= \frac{20}{3}

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What is the integral from 1 to 4 of (1+t)/(sqrt(t)) ?
The integral from 1 to 4 of (1+t)/(sqrt(t)) is 20/3