What is the integral from 0 to 5 of 1/(xsqrt(x)) ?

The integral from 0 to 5 of 1/(xsqrt(x)) is diverges

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integral from 0 to 5 of 1/(xsqrt(x))

\int_{0}^{5} \frac{1}{x x} d x

diverges

Solution steps

\int_{0}^{5} \frac{1}{x x} d x

Simplify

x x : x^{\frac{3}{2}}

= \int_{0}^{5} \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: [- \frac{2}{x}]_{0}^{5}

= [- \frac{2}{x}]_{0}^{5}

Compute the boundaries:

diverges

= diverges

\int_{2}^{4} 4 x^{3} d x

\int_{0}^{y - 1} \frac{3}{2} x^{2} d x

\int_{0}^{4} (6 - 6 x) d x

\int_{- 1}^{0} \frac{1}{- x} d x

\int_{1}^{4} 4 x^{3} + 5 x^{4} + 2 d x

What is the integral from 0 to 5 of 1/(xsqrt(x)) ?
The integral from 0 to 5 of 1/(xsqrt(x)) is diverges