What is the integral from 0 to 3 of (sqrt(x))^2 ?

The integral from 0 to 3 of (sqrt(x))^2 is 9/2

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integral from 0 to 3 of (sqrt(x))^2

\int_{0}^{3} (x)^{2} d x

\frac{9}{2}

Solution steps

\int_{0}^{3} (x)^{2} d x

Simplify

(x)^{2} : x

= \int_{0}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3}

= [\frac{x ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= \frac{9}{2}

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What is the integral from 0 to 3 of (sqrt(x))^2 ?
The integral from 0 to 3 of (sqrt(x))^2 is 9/2