What is the integral from 4 to 9 of xsqrt(x^2-4) ?

The integral from 4 to 9 of xsqrt(x^2-4) is (77sqrt(77))/3-8sqrt(3)

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integral from 4 to 9 of xsqrt(x^2-4)

\int_{4}^{9} x x^{2} - 4 d x

\frac{77 77}{3} - 83

Decimal Notation

211.36767 \dots

Solution steps

\int_{4}^{9} x x^{2} - 4 d x

Apply u-substitution

: \int_{23}^{77} u^{2} d u

= \int_{23}^{77} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{23}^{77}

= [\frac{u ^{3}}{3}]_{23}^{77}

Compute the boundaries:

\frac{77 77}{3} - 83

= \frac{77 77}{3} - 83

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What is the integral from 4 to 9 of xsqrt(x^2-4) ?
The integral from 4 to 9 of xsqrt(x^2-4) is (77sqrt(77))/3-8sqrt(3)