What is the integral from 2 to 3 of 1/(x^4) ?

The integral from 2 to 3 of 1/(x^4) is 19/648

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integral from 2 to 3 of 1/(x^4)

\int_{2}^{3} \frac{1}{x ^{4}} d x

\frac{19}{648}

Solution steps

\int_{2}^{3} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{2}^{3}

= [- \frac{1}{3 x ^{3}}]_{2}^{3}

Compute the boundaries:

\frac{19}{648}

= \frac{19}{648}

\int_{2}^{4} x^{2} e^{x^{3} + 5} d x

\int_{- 1}^{5} (4 x^{3} - 3 x^{2} + 1) x d x

\int_{2}^{y} x^{2} sin (x) d x

\int_{0}^{3} \frac{1}{3 + 2 ^{x}} d x

\int_{0}^{π} \frac{1}{n} cos (n x) d x

What is the integral from 2 to 3 of 1/(x^4) ?
The integral from 2 to 3 of 1/(x^4) is 19/648