What is the tangent of f(x)=sec(x),\at x=(pi/3) ?

The tangent of f(x)=sec(x),\at x=(pi/3) is y=2sqrt(3)x+2-(2pi)/(sqrt(3))

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tangent of f(x)=sec(x),\at x=(pi/3)

tangent of

f (x) = sec (x), at x = (\frac{π}{3})

y = 23 x + 2 - \frac{2 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 2)

Find the slope of

f (x) = sec (x) : \frac{df ( x )}{d x} = sec (x) tan (x)

Compute the slope of

f (x) = sec (x)

x = \frac{π}{3} : m = 23

Find the line with slope m=

23

and passing through

(\frac{π}{3}, 2) : y = 23 x + 2 - \frac{2 π}{3}

y = 23 x + 2 - \frac{2 π}{3}

x \to - 1 lim (a r cos (x))

\int \frac{2 + 3 cos ( x )}{sin ^{2} ( x )} d x

\int \frac{1}{20 + 8 x - x ^{2}} d x

\int_{0}^{2} 2 x d x

\frac{s + 5}{s ^{2} + 6 s + 18}

What is the tangent of f(x)=sec(x),\at x=(pi/3) ?
The tangent of f(x)=sec(x),\at x=(pi/3) is y=2sqrt(3)x+2-(2pi)/(sqrt(3))