What is the integral from-1 to 1 of x 3/4 (1-x^2) ?

The integral from-1 to 1 of x 3/4 (1-x^2) is 0

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integral from-1 to 1 of x 3/4 (1-x^2)

\int_{- 1}^{1} x \frac{3}{4} (1 - x^{2}) d x

0

Solution steps

\int_{- 1}^{1} x \frac{3}{4} (1 - x^{2}) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x \frac{3}{4} (1 - x^{2}) :

Odd

= 0

\int_{0}^{1} (3 x^{2} - 2 x)^{2} d x

\int_{0}^{t} \frac{1}{1 - x} d x

\int_{0}^{2} \frac{1}{x ^{2} + 4 x + 8} d x

\int_{0}^{1} \frac{6 x ^{2}}{1 - x ^{3}} d x

\int_{0}^{\frac{1}{2}} \frac{1}{1 + 4 y ^{2}} d y

What is the integral from-1 to 1 of x 3/4 (1-x^2) ?
The integral from-1 to 1 of x 3/4 (1-x^2) is 0