What is the integral from 0 to 2 of sec^3(x) ?

The integral from 0 to 2 of sec^3(x) is diverges

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integral from 0 to 2 of sec^3(x)

\int_{0}^{2} sec^{3} (x) d x

diverges

Solution steps

\int_{0}^{2} sec^{3} (x) d x

Take the denominator(s) of

sec^{3} (x)

and compare to zero:

x = \frac{π}{2}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{π}{2}} sec^{3} (x) d x + \int_{\frac{π}{2}}^{2} sec^{3} (x) d x

\int_{0}^{\frac{π}{2}} sec^{3} (x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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\int_{0}^{2.5} 127 \cdot 6.1 d x

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\int_{- 3}^{2} \frac{1}{2 - x} d x

\int_{0}^{3} k x (3 - x) d x

What is the integral from 0 to 2 of sec^3(x) ?
The integral from 0 to 2 of sec^3(x) is diverges