What is the integral from-infinity to 1 of 3e^{x/2} ?

The integral from-infinity to 1 of 3e^{x/2} is 6e^{1/2}

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integral from-infinity to 1 of 3e^{x/2}

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x

6 e^{\frac{1}{2}}

Decimal Notation

9.89232 \dots

Solution steps

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x

Compute the indefinite integral:

\int 3 e^{\frac{x}{2}} d x = 6 e^{\frac{x}{2}} + C

Compute the boundaries:

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x = 6 e^{\frac{1}{2}} - 0

= 6 e^{\frac{1}{2}} - 0

Simplify

= 6 e^{\frac{1}{2}}

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What is the integral from-infinity to 1 of 3e^{x/2} ?
The integral from-infinity to 1 of 3e^{x/2} is 6e^{1/2}