What is the integral from-infinity to 1 of 3e^{x/2} ?

The integral from-infinity to 1 of 3e^{x/2} is 6e^{1/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 1 of 3e^{x/2}

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x

6 e^{\frac{1}{2}}

Solution steps

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x

Compute the indefinite integral:

\int 3 e^{\frac{x}{2}} d x = 6 e^{\frac{x}{2}} + C

Compute the boundaries:

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x = 6 e^{\frac{1}{2}} - 0

= 6 e^{\frac{1}{2}} - 0

Simplify

= 6 e^{\frac{1}{2}}

\int_{0}^{y} x e^{y^{2}} d x

\int_{- 1}^{1} 2 - x^{2} - x^{2} d x

\int_{0}^{4} ∣ 1 - 2 x ∣ d x

\int_{- 1}^{0} \frac{3 t}{( 5 + t ^{2} ) ^{4}} d t

\int_{0}^{\frac{1}{2}} 96 x^{2} y^{3} d x

What is the integral from-infinity to 1 of 3e^{x/2} ?
The integral from-infinity to 1 of 3e^{x/2} is 6e^{1/2}