What is the integral from 7 to infinity of 7/(x^3) ?

The integral from 7 to infinity of 7/(x^3) is 1/14

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integral from 7 to infinity of 7/(x^3)

\int_{7}^{\infty} \frac{7}{x ^{3}} d x

\frac{1}{14}

Decimal Notation

0.07142 \dots

Solution steps

\int_{7}^{\infty} \frac{7}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{7}{x ^{3}} d x = - \frac{7}{2 x ^{2}} + C

Compute the boundaries:

\int_{7}^{\infty} \frac{7}{x ^{3}} d x = 0 - (- \frac{1}{14})

= 0 - (- \frac{1}{14})

Simplify

= \frac{1}{14}

\int_{0}^{0} x d x

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\int_{0}^{\frac{π}{2}} e^{x} + cos (x) d x

What is the integral from 7 to infinity of 7/(x^3) ?
The integral from 7 to infinity of 7/(x^3) is 1/14