What is the integral from-2 to 0 of 5x^4-3x^2+x-3 ?

The integral from-2 to 0 of 5x^4-3x^2+x-3 is 16

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integral from-2 to 0 of 5x^4-3x^2+x-3

\int_{- 2}^{0} 5 x^{4} - 3 x^{2} + x - 3 d x

16

Solution steps

\int_{- 2}^{0} 5 x^{4} - 3 x^{2} + x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} 5 x^{4} d x - \int_{- 2}^{0} 3 x^{2} d x + \int_{- 2}^{0} x d x - \int_{- 2}^{0} 3 d x

\int_{- 2}^{0} 5 x^{4} d x = 32

\int_{- 2}^{0} 3 x^{2} d x = 8

\int_{- 2}^{0} x d x = - 2

\int_{- 2}^{0} 3 d x = 6

= 32 - 8 - 2 - 6

Simplify

= 16

\int_{- π}^{π} sin^{4} (x) cos (x) d x

\int_{0}^{10} 5 x - 3 d x

\int_{0}^{1} (e^{t} + e^{- t}) d t

\int_{1}^{4} 9

\int_{0}^{1} y^{x} d x

What is the integral from-2 to 0 of 5x^4-3x^2+x-3 ?
The integral from-2 to 0 of 5x^4-3x^2+x-3 is 16