What is the integral from 1/2 to 1 of (sin(x))/x ?

The integral from 1/2 to 1 of (sin(x))/x is 0.9460830704-\Si(1/2)

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integral from 1/2 to 1 of (sin(x))/x

\int_{\frac{1}{2}}^{1} \frac{sin ( x )}{x} d x

0.9460830704 - Si (\frac{1}{2})

Solution steps

\int_{\frac{1}{2}}^{1} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{\frac{1}{2}}^{1}

Compute the boundaries:

0.9460830704 - Si (\frac{1}{2})

= 0.9460830704 - Si (\frac{1}{2})

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What is the integral from 1/2 to 1 of (sin(x))/x ?
The integral from 1/2 to 1 of (sin(x))/x is 0.9460830704-\Si(1/2)