What is the integral from 1 to 4 of 1/(2y) ?

The integral from 1 to 4 of 1/(2y) is ln(2)

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integral from 1 to 4 of 1/(2y)

\int_{1}^{4} \frac{1}{2 y} d y

ln (2)

Solution steps

\int_{1}^{4} \frac{1}{2 y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{4} \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= \frac{1}{2} [ln ∣ y ∣]_{1}^{4}

Compute the boundaries:

2 ln (2)

= \frac{1}{2} \cdot 2 ln (2)

Simplify

= ln (2)

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\int_{- 2}^{3} \frac{1}{( x ^{4} )} d x

What is the integral from 1 to 4 of 1/(2y) ?
The integral from 1 to 4 of 1/(2y) is ln(2)