What is the derivative of 3x^5-2x^4-4x^3 ?

The derivative of 3x^5-2x^4-4x^3 is 15x^4-8x^3-12x^2

What is the first derivative of 3x^5-2x^4-4x^3 ?

The first derivative of 3x^5-2x^4-4x^3 is 15x^4-8x^3-12x^2

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\frac{d}{d x} (3 x^{5} - 2 x^{4} - 4 x^{3})

15 x^{4} - 8 x^{3} - 12 x^{2}

Solution steps

\frac{d}{d x} (3 x^{5} - 2 x^{4} - 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{5}) - \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (4 x^{3})

\frac{d}{d x} (3 x^{5}) = 15 x^{4}

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

= 15 x^{4} - 8 x^{3} - 12 x^{2}

(y - x^{2} + y^{2}) d x - x d y = 0

\frac{d}{d x} (x ln (x^{6}))

f (x) = 110 x - 16 x^{2}, at 3

7 x

\frac{d x}{d t} = (\frac{( e ^{t} x + 1 )}{1 - e ^{t}})

What is the derivative of 3x^5-2x^4-4x^3 ?
The derivative of 3x^5-2x^4-4x^3 is 15x^4-8x^3-12x^2
What is the first derivative of 3x^5-2x^4-4x^3 ?
The first derivative of 3x^5-2x^4-4x^3 is 15x^4-8x^3-12x^2