What is the integral from-2 to 1 of (3x^2-6x+2) ?

The integral from-2 to 1 of (3x^2-6x+2) is 24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 1 of (3x^2-6x+2)

\int_{- 2}^{1} (3 x^{2} - 6 x + 2) d x

24

Solution steps

\int_{- 2}^{1} 3 x^{2} - 6 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 3 x^{2} d x - \int_{- 2}^{1} 6 x d x + \int_{- 2}^{1} 2 d x

\int_{- 2}^{1} 3 x^{2} d x = 9

\int_{- 2}^{1} 6 x d x = - 9

\int_{- 2}^{1} 2 d x = 6

= 9 - (- 9) + 6

Simplify

= 24

\int_{- 3}^{1} \frac{1}{( x + 1 ) ^{2}} d x

\int_{0}^{y} 9 + y^{2} d y

\int_{0}^{3 π} sin^{5} (x) d x

\int_{0}^{\frac{π}{6}} x sin (6 x) d x

\int_{0}^{1} r 2 - r^{2} - r^{2} d r

What is the integral from-2 to 1 of (3x^2-6x+2) ?
The integral from-2 to 1 of (3x^2-6x+2) is 24