What is the integral from 1 to 0 of 1/(sqrt(x)) ?

The integral from 1 to 0 of 1/(sqrt(x)) is -2

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integral from 1 to 0 of 1/(sqrt(x))

\int_{1}^{0} \frac{1}{x} d x

- 2

Solution steps

\int_{1}^{0} \frac{1}{x} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{0}^{1}

= - [2 x^{\frac{1}{2}}]_{0}^{1}

Apply radical rule:

= - [2 x]_{0}^{1}

Compute the boundaries:

2

= - 2

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What is the integral from 1 to 0 of 1/(sqrt(x)) ?
The integral from 1 to 0 of 1/(sqrt(x)) is -2