What is the integral from x^2+3 to 4x of 1 ?

The integral from x^2+3 to 4x of 1 is 4x-x^2-3

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integral from x^2+3 to 4x of 1

\int_{x^{2} + 3}^{4 x} 1 d y

4 x - x^{2} - 3

Solution steps

\int_{x^{2} + 3}^{4 x} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x^{2} + 3}^{4 x}

Simplify

= [y]_{x^{2} + 3}^{4 x}

Compute the boundaries:

4 x - x^{2} - 3

= 4 x - x^{2} - 3

\int_{0}^{3} x (1.33 x^{2} - 3) d x

\int_{1}^{7} e^{x} d x

\int_{1}^{4} x ln (2) - \frac{3}{2 x} d x

\int_{2}^{10} (5 x^{2} - 2) d x

\int_{0}^{1} x^{4} - 1 d x

What is the integral from x^2+3 to 4x of 1 ?
The integral from x^2+3 to 4x of 1 is 4x-x^2-3