What is the integral from 1 to 2 of xsqrt(x^2-2) ?

The integral from 1 to 2 of xsqrt(x^2-2) is (2sqrt(2))/3+i 1/3

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integral from 1 to 2 of xsqrt(x^2-2)

\int_{1}^{2} x x^{2} - 2 d x

\frac{2 2}{3} + i \frac{1}{3}

Solution steps

\int_{1}^{2} x x^{2} - 2 d x

Apply u-substitution

: \int_{i}^{2} u^{2} d u

= \int_{i}^{2} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{i}^{2}

= [\frac{u ^{3}}{3}]_{i}^{2}

Compute the boundaries:

\frac{2 2}{3} + i \frac{1}{3}

= \frac{2 2}{3} + i \frac{1}{3}

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What is the integral from 1 to 2 of xsqrt(x^2-2) ?
The integral from 1 to 2 of xsqrt(x^2-2) is (2sqrt(2))/3+i 1/3