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Popular >

integral from-1 to 2 of (4x+1)

Solution

\int_{- 1}^{2} (4 x + 1) d x

Solution

9

Solution steps

\int_{- 1}^{2} 4 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 4 x d x + \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} 4 x d x = 6

\int_{- 1}^{2} 1 d x = 3

= 6 + 3

Simplify

= 9

Popular Examples

integral from 0 to 2 of 8x-3+5e^{2-x}

\int_{0}^{2} 8 x - 3 + 5 e^{2 - x} d x

integral from-infinity to-7 of e^x

\int_{- \infty}^{- 7} e^{x} d x

integral from y to 1 of (ye^x-y)

\int_{y}^{1} (y e^{x} - y) d x

integral from-2 to 5 of-2x^2+6x+20

\int_{- 2}^{5} - 2 x^{2} + 6 x + 20 d x

integral from 0 to 75 of 46*x)

\int_{0}^{75} 46 \cdot d (x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (4x+1) ?
The integral from-1 to 2 of (4x+1) is 9