What is the integral from-3 to 3 of 3^x ?

The integral from-3 to 3 of 3^x is (728)/(27ln(3))

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integral from-3 to 3 of 3^x

\int_{- 3}^{3} 3^{x} d x

\frac{728}{27 ln ( 3 )}

Decimal Notation

24.54274 \dots

Solution steps

\int_{- 3}^{3} 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{3 ^{x}}{ln ( 3 )}]_{- 3}^{3}

Compute the boundaries:

\frac{728}{27 ln ( 3 )}

= \frac{728}{27 ln ( 3 )}

\int_{1}^{3} 21 t^{2} d t

\int_{12}^{5} (12 - 6 x) d x

\int_{- 1}^{1} - u^{2} + 1 d u

\int_{0}^{1} \frac{1}{x ^{a}} d x

\int_{1}^{t} \frac{1}{x ^{2} + 4} d x

What is the integral from-3 to 3 of 3^x ?
The integral from-3 to 3 of 3^x is (728)/(27ln(3))