What is the integral from-1 to 1 of (x^5)/(x^2+25) ?

The integral from-1 to 1 of (x^5)/(x^2+25) is 0

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integral from-1 to 1 of (x^5)/(x^2+25)

\int_{- 1}^{1} \frac{x ^{5}}{x ^{2} + 25} d x

0

Solution steps

\int_{- 1}^{1} \frac{x ^{5}}{x ^{2} + 25} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x ^{5}}{x ^{2} + 25} :

Odd

= 0

\int_{\frac{π}{2}}^{\frac{3 π}{4}} 1

\int_{0}^{y} c e^{- 2 y} d x

\int_{0}^{1} (x - x^{2}) (e^{x}) d x

\int_{- 1}^{2} (x^{2} - 5 x) d x

\int_{0}^{1} π (- ln (x))^{2} d x

What is the integral from-1 to 1 of (x^5)/(x^2+25) ?
The integral from-1 to 1 of (x^5)/(x^2+25) is 0