What is the integral from 0 to pi^2 of cos(x) ?

The integral from 0 to pi^2 of cos(x) is sin(pi^2)

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integral from 0 to pi^2 of cos(x)

\int_{0}^{π^{2}} cos (x) d x

sin (π^{2})

Solution steps

\int_{0}^{π^{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{π^{2}}

Compute the boundaries:

sin (π^{2})

= sin (π^{2})

\int_{- 1}^{1} 2 x sin (nπ x) d x

\int_{30}^{200} 50 x - 30 d x

\int_{0}^{1} e^{- s t} (t e^{t}) d t

\int_{0}^{1} π x^{3} d x

\int_{0}^{1} (\frac{x}{e ^{2 x}}) d x

What is the integral from 0 to pi^2 of cos(x) ?
The integral from 0 to pi^2 of cos(x) is sin(pi^2)