What is the integral from 0 to 0.5 of Cx ?

The integral from 0 to 0.5 of Cx is C*0.125

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integral from 0 to 0.5 of Cx

\int_{0}^{0.5} C x d x

C \cdot 0.125

Solution steps

\int_{0}^{0.5} C x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= C \cdot \int_{0}^{0.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.5}

= C [\frac{x ^{2}}{2}]_{0}^{0.5}

Simplify

= C [0.5 x^{2}]_{0}^{0.5}

Compute the boundaries:

0.125

= C \cdot 0.125

\int_{0}^{7} x x + 2 d x

\int_{0}^{5} (75 - 3 x^{2}) d x

\int_{0}^{1} \frac{x ^{2} tan ( x ^{3} )}{4} d x

\int_{0}^{1.5} 2 e^{- 2 x} d x

\int_{0}^{5} (3 - 2 x + x^{2}) d x

What is the integral from 0 to 0.5 of Cx ?
The integral from 0 to 0.5 of Cx is C*0.125