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Popular >

integral from 1 to 4 of-x^2+8x

Solution

\int_{1}^{4} - x^{2} + 8 x d x

Solution

39

Solution steps

\int_{1}^{4} - x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{4} x^{2} d x + \int_{1}^{4} 8 x d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 8 x d x = 60

= - 21 + 60

Simplify

= 39

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of-x^2+8x ?
The integral from 1 to 4 of-x^2+8x is 39