What is the integral from x+2 to 4-x^2 of 1 ?

The integral from x+2 to 4-x^2 of 1 is -x^2-x+2

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integral from x+2 to 4-x^2 of 1

\int_{x + 2}^{4 - x^{2}} 1 d y

- x^{2} - x + 2

Solution steps

\int_{x + 2}^{4 - x^{2}} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x + 2}^{4 - x^{2}}

Simplify

= [y]_{x + 2}^{4 - x^{2}}

Compute the boundaries:

- x^{2} - x + 2

= - x^{2} - x + 2

\int_{0}^{2} (3 t^{3} + 5 t) d t

\int_{0}^{t} i (t) d t

\int_{1}^{9} x - 1 d x

\int_{1}^{2} \frac{1}{1 + x ^{2}} d x

\int_{0}^{t} (t + 2) d t

What is the integral from x+2 to 4-x^2 of 1 ?
The integral from x+2 to 4-x^2 of 1 is -x^2-x+2