What is the integral from 0 to x of (e^{x^2}) ?

The integral from 0 to x of (e^{x^2}) is (sqrt(pi))/2 \erfi(x)

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integral from 0 to x of (e^{x^2})

\int_{0}^{x} (e^{x^{2}}) d x

\frac{π}{2} erfi (x)

Solution steps

\int_{0}^{x} e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= [\frac{π}{2} erfi (x)]_{0}^{x}

Compute the boundaries:

\frac{π}{2} erfi (x)

= \frac{π}{2} erfi (x)

\int_{- π}^{0} π - x d x

\int_{0}^{2 π} cos (t) 2 d t

\int_{1}^{e^{t}} \frac{( ln ( x ) ) ^{2}}{x} d x

\int_{- 1}^{1} \frac{2}{1 + 4 t ^{2}} d t

\int_{4}^{6} x (\frac{1}{x - 3}) d x

What is the integral from 0 to x of (e^{x^2}) ?
The integral from 0 to x of (e^{x^2}) is (sqrt(pi))/2 \erfi(x)