What is the integral from-8 to infinity of 1/(x+9) ?

The integral from-8 to infinity of 1/(x+9) is diverges

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integral from-8 to infinity of 1/(x+9)

\int_{- 8}^{\infty} \frac{1}{x + 9} d x

diverges

Solution steps

\int_{- 8}^{\infty} \frac{1}{x + 9} d x

Compute the indefinite integral:

\int \frac{1}{x + 9} d x = ln ∣ x + 9 ∣ + C

Compute the boundaries:

\int_{- 8}^{\infty} \frac{1}{x + 9} d x =

diverges

= diverges

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What is the integral from-8 to infinity of 1/(x+9) ?
The integral from-8 to infinity of 1/(x+9) is diverges