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Popular >

integral from 2 to 4 of (6-x-y)

Solution

\int_{2}^{4} (6 - x - y) d y

Solution

- 2 x + 6

Solution steps

\int_{2}^{4} 6 - x - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 6 d y - \int_{2}^{4} x d y - \int_{2}^{4} y d y

\int_{2}^{4} 6 d y = 12

\int_{2}^{4} x d y = 2 x

\int_{2}^{4} y d y = 6

= 12 - 2 x - 6

Simplify

= - 2 x + 6

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\int_{0}^{\infty} e^{- 7 x^{2}} d x

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\int_{- 1}^{1} e^{y} sin (y) d y

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\int_{0}^{5} 2 e^{- 2 x} d x

Frequently Asked Questions (FAQ)

What is the integral from 2 to 4 of (6-x-y) ?
The integral from 2 to 4 of (6-x-y) is -2x+6