What is the integral from 4 to 7 of (2x^2-x) ?

The integral from 4 to 7 of (2x^2-x) is 339/2

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integral from 4 to 7 of (2x^2-x)

\int_{4}^{7} (2 x^{2} - x) d x

\frac{339}{2}

Decimal Notation

169.5

Solution steps

\int_{4}^{7} 2 x^{2} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{7} 2 x^{2} d x - \int_{4}^{7} x d x

\int_{4}^{7} 2 x^{2} d x = 186

\int_{4}^{7} x d x = \frac{33}{2}

= 186 - \frac{33}{2}

Simplify

186 - \frac{33}{2} : \frac{339}{2}

= \frac{339}{2}

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What is the integral from 4 to 7 of (2x^2-x) ?
The integral from 4 to 7 of (2x^2-x) is 339/2