What is the integral from 5 to infinity of e^{-2x} ?

The integral from 5 to infinity of e^{-2x} is 1/(2e^{10)}

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integral from 5 to infinity of e^{-2x}

\int_{5}^{\infty} e^{- 2 x} d x

\frac{1}{2 e ^{10}}

Decimal Notation

0.00002 \dots

Solution steps

\int_{5}^{\infty} e^{- 2 x} d x

Compute the indefinite integral:

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + C

Compute the boundaries:

\int_{5}^{\infty} e^{- 2 x} d x = 0 - (- \frac{1}{2 e ^{10}})

= 0 - (- \frac{1}{2 e ^{10}})

Simplify

= \frac{1}{2 e ^{10}}

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What is the integral from 5 to infinity of e^{-2x} ?
The integral from 5 to infinity of e^{-2x} is 1/(2e^{10)}