What is the integral from 2 to 5 of 6x^{-2} ?

The integral from 2 to 5 of 6x^{-2} is 9/5

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integral from 2 to 5 of 6x^{-2}

\int_{2}^{5} 6 x^{- 2} d x

\frac{9}{5}

Decimal Notation

1.8

Solution steps

\int_{2}^{5} 6 x^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{2}^{5} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{5}

= 6 [- \frac{1}{x}]_{2}^{5}

Compute the boundaries:

\frac{3}{10}

= 6 \cdot \frac{3}{10}

Simplify

= \frac{9}{5}

\int_{4}^{7} e^{2 x + 1} d x

\int_{2}^{1} (1 + \frac{z}{2}) d z

\int_{1}^{x} sin (x) d x

\int_{0}^{1} e^{x} - e^{- 2 x} d x

\int_{0}^{5} 5 - x^{2} d x

What is the integral from 2 to 5 of 6x^{-2} ?
The integral from 2 to 5 of 6x^{-2} is 9/5