What is the limit as x approaches pi/2 of (sin(x))/(cos(x)) ?

The limit as x approaches pi/2 of (sin(x))/(cos(x)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches pi/2 of (sin(x))/(cos(x))

x \to \frac{π}{2} lim (\frac{sin ( x )}{cos ( x )})

diverges

Solution steps

x \to \frac{π}{2} lim (\frac{sin ( x )}{cos ( x )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to \frac{π}{2} + lim (\frac{sin ( x )}{cos ( x )}) = - \infty

x \to \frac{π}{2} - lim (\frac{sin ( x )}{cos ( x )}) = \infty

= diverges

x \to π lim (\frac{sin ( x )}{2 + cos ( x )})

x \to - 1 lim (6 x^{3} - 7 x + 12)

x \to 3 - lim (2 e^{x - 3})

x \to 0 + lim (3 (tan (x))^{x})

x \to 0 lim (\frac{4 x - 2 x ^{2}}{sin ( x )})

What is the limit as x approaches pi/2 of (sin(x))/(cos(x)) ?
The limit as x approaches pi/2 of (sin(x))/(cos(x)) is diverges