What is the solution for y^'+y*tan(x)= 1/(cos(x)) ?

The solution for y^'+y*tan(x)= 1/(cos(x)) is y=(tan(x))/(sec(x))+(c_{1})/(sec(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y*tan(x)= 1/(cos(x))

y^{^{'}} + y \cdot tan (x) = \frac{1}{cos ( x )}

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

Solution steps

y^{'} (x) + y \cdot tan (x) = \frac{1}{cos ( x )}

Solve linear ODE:

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

ln (1 + 12 x)

x + 16

\frac{\partial}{\partial x} (10 x yz)

\frac{d}{d x} (27 e^{3 x})

\int (4 x^{3} + 1) ln (x) d x

What is the solution for y^'+y*tan(x)= 1/(cos(x)) ?
The solution for y^'+y*tan(x)= 1/(cos(x)) is y=(tan(x))/(sec(x))+(c_{1})/(sec(x))