What is the solution for t*(dy)/(dt)+34y= 1/t ?

The solution for t*(dy)/(dt)+34y= 1/t is y= 1/(33t)+(c_{1})/(t^{34)}

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t*(dy)/(dt)+34y= 1/t

t \cdot \frac{d y}{d t} + 34 y = \frac{1}{t}

y = \frac{1}{33 t} + \frac{c _{1}}{t ^{34}}

Solution steps

t \cdot \frac{d y}{d t} + 34 y = \frac{1}{t}

Solve linear ODE:

y = \frac{1}{33 t} + \frac{c _{1}}{t ^{34}}

y = \frac{1}{33 t} + \frac{c _{1}}{t ^{34}}

v + t v^{^{'}} = \frac{( 4 + v )}{( 4 v - 1 )}

y^{^{'}} = 7 x - y

f (x) = 3 x^{5} (x^{3} - 2 x)

\int \frac{3}{2 9 - x ^{2}} d x

\int e^{3 x} + 1 d x

What is the solution for t*(dy)/(dt)+34y= 1/t ?
The solution for t*(dy)/(dt)+34y= 1/t is y= 1/(33t)+(c_{1})/(t^{34)}