What is the derivative of \sqrt[3]{x}(2+x) ?

The derivative of \sqrt[3]{x}(2+x) is (2+x)/(3x^{2/3)}+\sqrt[3]{x}

What is the first derivative of \sqrt[3]{x}(2+x) ?

The first derivative of \sqrt[3]{x}(2+x) is (2+x)/(3x^{2/3)}+\sqrt[3]{x}

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derivative of

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (2 + x) = 1

Simplify

7 (x^{2} + y^{2}) d x + 2 x y d y = 0

\int e^{- 4 x} cos (3 x) d x

\frac{d}{d x} (- ln (x) + x^{2})

\int_{- 6}^{8} (\frac{x}{2} + 8) d x

\int \frac{3 t ^{2}}{2} d t

What is the derivative of \sqrt[3]{x}(2+x) ?
The derivative of \sqrt[3]{x}(2+x) is (2+x)/(3x^{2/3)}+\sqrt[3]{x}
What is the first derivative of \sqrt[3]{x}(2+x) ?
The first derivative of \sqrt[3]{x}(2+x) is (2+x)/(3x^{2/3)}+\sqrt[3]{x}